9x^2+8=233

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Solution for 9x^2+8=233 equation:



9x^2+8=233
We move all terms to the left:
9x^2+8-(233)=0
We add all the numbers together, and all the variables
9x^2-225=0
a = 9; b = 0; c = -225;
Δ = b2-4ac
Δ = 02-4·9·(-225)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*9}=\frac{-90}{18} =-5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*9}=\frac{90}{18} =5 $

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